RSA加密实例分析
现在网上有的大部分都是理论，这里将给出一个简单加密模块的全部源程序（源代码）
至于RSA的理论网上一大把，它是基于公钥加密体制的一种算法。这个实例主要是用来将某一重要文件绑定到一个IP地址上。把它拷贝下来，存为CODE.C，然后执行
GCC –O CODE CODE.C
然后用./ CODE E [IP ADDRESS] [FILENAME]对文件进行加密。或用
./CODE D [IP ADDRESS] 进行解密整个过程中产生了两个中间文件,至于什么文件,你去试一试就知道啦!
#include "stdio.h"
#include "string.h"
int e,d=1,n;
main(int argc,char *argv[])
{
int ip,fai,p=43,q=59,ch1,i=0,j=0,edch,dech=0;
char *num,*cha,ch,*file={"index.html"};
FILE *fp,*fp2;
if (argc<2)
{
printf("paramater error!");
exit(0);
}
if (argc>3)
{
file=argv[3];
}
//printf("%s,",file)
e=iptoint(argv[2]);
//printf("%s,%s",argv[1],argv[2]);
switch (*argv[1])
{
case e:
//printf("e=%d",e);
if ((fp2=fopen("encode.htm","w+"))==NULL)
{
printf("can open file");
exit(0);
}
"code.c" 199L, 3571C
}
n=p*q;fai=(p-1)*(q-1);
if((fp=fopen(file,"r"))==NULL)
{
printf("can open giving file");
exit(0);
}
else
{
while((ch1=fgetc(fp))!=EOF)
{
edch=fmod(ch1,e,n);
if (edch>0 && edch<10)
{ fprintf(fp2,"%s","000"); fprintf(fp2,"%d",edch);
}
else if (edch<100 && edch>10)
{ fprintf(fp2,"%s","00"); fprintf(fp2,"%d",edch);
}
else if (edch<1000 && edch>100)
{ fprintf(fp2,"%s","0"); fprintf(fp2,"%d",edch);
}
else if (edch<10000 && edch>1000)
{ fprintf(fp2,"%d",edch);
}
else
fputc(\
,fp2);
}
}
close(fp);
close(fp2);
break;
case d:
// printf("d=%d",e);
if ((fp2=fopen("decode.html","w+"))==NULL)
{
if ((fp2=fopen("decode.html","w+"))==NULL)
{
printf("can open file");
exit(0);
}
n=p*q;fai=(p-1)*(q-1);
while(((d*e)%fai)!=1)
d++;
if((fp=fopen("encode.htm","r"))==NULL)
{
printf("can open file");
exit(0);
}
else
{ i=0;
// printf("e=%d,d=%d,n=%d,",e,d,n);
while((ch=fgetc(fp))!=EOF)
{
if (i==4)
{
//dech=((int)num[0])*1000+((int)num[1])*100+((int)num[2])*10+(int)num[3];
//printf("yuan=%d,",dech);
dech=fmod(dech,d,n);
//printf("new=%d,",dech);
fprintf(fp2,"%c",dech);
i=0;
dech=0;
//
}
switch (ch)
{
case 9:dech=dech*10+9;break;
case 1:dech=dech*10+1;break;
case 2:dech=dech*10+2;break;
case 3:dech=dech*10+3;break;
case 4:dech=dech*10+4;break;
case 3:dech=dech*10+3;break;
case 4:dech=dech*10+4;break;
case 5:dech=dech*10+5;break;
case 6:dech=dech*10+6;break;
case 7:dech=dech*10+7;break;
case 8:dech=dech*10+8;break;
default:dech=dech*10;
}
// printf("dech=%d,",dech);
num[i]=ch;
i++;
}
dech=fmod(dech,d,n);
fprintf(fp2,"%c",dech);
}
close(fp);
close(fp2);
break;
default:
printf("Usage:code [option]...[Ip Address]...\n");
printf("List information about the option\n");
printf("e bind ip address to index.html\n");
printf("d decode from the encodeing file to index2.html");
}
}
int iptoint(ip)
char *ip;
{
int i,ei=0,len;
int prime=0;
len=strlen(ip);
len=strlen(ip);
for(i=0;i<len;i++)
{
if(ip[i]> && ip[i]<9)
ei=ei+i*((int)ip[i]);
}
ei=ei/1000+(ei/100)%10+(ei/10)%10+ei%10;
//printf("%d",ei);
//len=ei/2;
//while(prime==0)
//indent: Standard input:2: Error:Unexpected end of file
while (((ei % 2)== 0) || ((ei % 3) == 0))
{ ei=ei+1;
}
/* prime=1;
for (i=0;i<ei;i++)
{
if((ei%i)==0)
{
ei--;
prime=0;
break;
}
}
}*/
return(ei);
}
int fmod(x, r, p)
int x,r,p;
{
int a,b,c=1;
a=x;b=r;
while (b!=0)
{
while ((b%2)==0)
{
b=b/2;a=(a*a)%p;
}
b=b-1;c=(a*c)%p;
}
return c;
}
摘自：泡吧
发布人:netbull 来自:非常Linux